How to solve the matrix equation <mml:math altimg="si1.gif" overflow="scroll" xmlns:xocs="http://www.elsevier.com/xml/xocs/dtd" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://www.elsevier.com/xml/ja/dtd" xmlns:ja="http://www.elsevier.com/xml/ja/dtd" xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:tb="http://www.elsevier.com/xml/common/table/dtd" xmlns:sb="http://www.elsevier.com/xml/common/struct-bib/dtd" xmlns:ce="http://www.elsevier.com/xml/common/dtd" xmlns:xlink="http://www.w3.org/1999/xlink" xmlns:cals="http://www.elsevier.com/xml/common/cals/dtd"><mml:mrow><mml:mi mathvariant="italic">XA</mml:mi><mml:mo>-</mml:mo><mml:mi mathvariant="italic">AX</mml:mi><mml:mo>=</mml:mo><mml:mi>f</mml:mi><mml:mo stretchy="false">(</mml:mo><mml:mi>X</mml:mi><mml:mo stretchy="false">)</mml:mo></mml:mrow></mml:math> - Université de la Polynésie française
Article Dans Une Revue Linear Algebra and its Applications Année : 2011

How to solve the matrix equation XA-AX=f(X)

Dates et versions

hal-03417851 , version 1 (05-11-2021)

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Gerald Bourgeois. How to solve the matrix equation XA-AX=f(X). Linear Algebra and its Applications, 2011, 434 (3), pp.657-668. ⟨10.1016/j.laa.2010.09.037⟩. ⟨hal-03417851⟩

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